the length of the tv screen is,
l = 41 cm
the width of the tv is
b = 31 cm
the length of the diagonal will be the hypotenuse of the triangle,
so, diagonal length is,
[tex]\text{diagonal}=\sqrt[]{41^2+31^2}[/tex][tex]\text{diagonal}=\sqrt[]{1681+961}[/tex][tex]\begin{gathered} \text{diagonal}=\sqrt[]{2642} \\ \text{diagonal}=51.04 \end{gathered}[/tex]so, the length of the diagonal is closest 51.04 cm
