Respuesta :

Solution

For this case we know that:

a1= 7

[tex]a_n=3a_{n-1}+4[/tex]

Then for a4 we have:

[tex]a_4=3a_3+4=3(3a_2+4)+4=9a_2+16=9(3a_1+4)+16=27a_1+36+16[/tex]

And then we can replace and we got:

a4= 27*7 +52= 241

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