JakeHamann13 JakeHamann13
  • 30-11-2021
  • Mathematics
contestada

Find the first partial derivatives of the function.
z = (6x + 2y)^9

dz/dx=
dz/dy=

Respuesta :

LammettHash
LammettHash LammettHash
  • 30-11-2021

If z = (6x + 2y)⁹, then the partial derivatives of z are

• with respect to x :

∂z/∂x = 9 (6x + 2y)⁹⁻¹ • ∂(6x + 2y)/∂x

∂z/∂x = 9 (6x + 2y)⁸ • 6

∂z/∂x = 54 (6x + 2y)⁸

• with respect to y :

∂z/∂y = 9 (6x + 2y)⁹⁻¹ • ∂(6x + 2y)/∂y

∂z/∂y = 9 (6x + 2y)⁸ • 2

∂z/∂y = 18 (6x + 2y)⁸

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