ria2389
ria2389 ria2389
  • 31-03-2019
  • Mathematics
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Plz help me !!!!!!!!!

Plz help me class=

Respuesta :

tramserran
tramserran tramserran
  • 31-03-2019

Answer:   [tex]\bold{x^{\frac{1}{3}}y^{\frac{1}{2}}}[/tex]

Step-by-step explanation:

[tex]\sqrt[6]{x^2y^3} =x^{\frac{2}{6}}y^{\frac{3}{6}}=x^{\frac{1}{3}}y^{\frac{1}{2}}[/tex]

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