m3rk098 m3rk098
  • 28-04-2018
  • Mathematics
contestada

hey can you please help me posted picture of question

hey can you please help me posted picture of question class=

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ag6567
ag6567 ag6567
  • 28-04-2018
The solutions for the equation, [tex]2x^2-5x+1=0[/tex], are D and E.
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carlosego
carlosego carlosego
  • 28-04-2018
We have the following equation:
 2x2-5x + 1 = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 Substituting values we have:
 x = (- (- 5) +/- root ((- 5) 2 - 4 (2) (1))) / 2 (2)
 Rewriting:
 x = (5 +/- root (25 - 8)) / 4
 x = (5 +/- root (17)) / 4
 The results are:
 x = (5 + root (17)) / 4
 x = (5 - root (17)) / 4
 Answer:
 
x = (5 + root (17)) / 4
 
x = (5 - root (17)) / 4
 
option D and E
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