Answer:
\frac{1}{8} (sin 5+sin 3)
Step-by-step explanation:
step 1:-
average value of given function =[tex]\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx[/tex]
[[tex]\frac{1}{8}(sin 5-(sin(-3)) \\\\\frac{1}{8} (sin 5+sin 3)[/tex]
Final answer:-
\frac{1}{8} (sin 5+sin 3)
