gandrapreetam gandrapreetam
  • 30-03-2018
  • Mathematics
contestada

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

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altavistard
altavistard altavistard
  • 31-03-2018
Note that (a+b)^2 = a^2 + 2ab + b^2.  This is always true.

Let's re-write the given "ab = 8 and a^2+b^2=16" as
  a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as 
       (a+b)^2          = 16 + 2(8) = 32. 
 This is the answer we wanted.




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