The vector equation of the line through the origin perpendicular to the plane is .. (x, y, z) = t(2, 3, -1) so the point of interest will satisfy .. 2(2t) +3(3t) -(-t) = -3 .. 14t = -3 .. t = -3/14 and its coordinates are (x, y, z) = (-3/7, -9/14, 3/14)
