[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1200\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
n=
\begin{array}{llll}
\textit{times it compounds per year}
\end{array}\to &4\\
t=years\to &6
\end{cases}
\\\\\\
A=1200\left(1+\frac{0.065}{4}\right)^{4\cdot 6}\implies A=1200(1.01625)^{24}[/tex]
