Respuesta :

abscisa15

[tex]\it \begin{cases}\it4x+5y=7 \\\;\\ \it y=3x+9 \ \ \ \ (*) \end{cases}[/tex]


[tex]\it 4x+5y=7 \stackrel{(*)}{\Longrightarrow} 4x+5(3x+9) = 7 \Rightarrow 4x+15x+ 45 =7 \Rightarrow \\\;\\ \Rightarrow 4x+15x=7-45 \Rightarrow 19x= -38 \Rightarrow x = \dfrac{-38}{19} \Rightarrow x= -2[/tex]



[tex]\it x=-2 \stackrel{(*)}{\Longrightarrow} y=3\cdot(-2) +9 \Rightarrow y=-6+9 \Rightarrow y=3 \\\;\\ So,\ we\ have: \begin{cases} \it x=-2 \\\;\\ \it y=3\end{cases}[/tex]





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