I'm guessing you mean:
[tex]A = 169 \sqrt{2} [/tex]
If not, correct me.
So, then the perimeter of a square is just 4*A, which in this case would be:
[tex]4(169 \sqrt{2}) = 676 \sqrt{2} [/tex]
And that would be your answer: [tex]676 \sqrt{2} [/tex] units²
