Answer:
Step-by-step explanation:
Henry subtracted ( 3p+5)/3p from ( [tex](\frac{p+3}{p-2})[/tex] and got
[tex]\frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)}[/tex]
We have simplify the difference
= [tex]\frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)}[/tex] = [tex]\frac{(12p^{2}-3p^{2})+(9p+p)+10}{(p-2)(3p)}[/tex]
= [tex]\frac{9p^{2}+10p+10}{(p-2)(3p)}[/tex]
