After 1 half-life, 12 of the C-14 would remain. After 2 half-life, 12 of the 12 of the C-14 = 14 of the C-14 would remain. After 3 half-life, 12 of the 14 of the C-14 = 18 of the C-14 would remain. ...After n half-lives, 12n of the C-14 would remain. Was this helpful? Let the contributor know! Yes. Post comment 1500
