preferredproceox0hpk
preferredproceox0hpk preferredproceox0hpk
  • 31-10-2017
  • Mathematics
contestada

Suppose you had to find 4 x 57. How are the expanded algorithm and the standard algorithm alike? And how are they different?

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nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 12-11-2017
The expanded algorithm is given as follows:

4 x 57 = (4 x 50) + (4 x 7) = 200 + 28 = 228


The standard algorithm is given as follows:

[tex]\ \ \ \ \ \ {_2}\\{ \ \ \ \ \ \ 5 \ 7} \\ \times \ \ \ \ \ 4 \\ = \overline{\underline{2\ 2\ 8}}[/tex]
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