Data:
M = 1.50 (assiming the data is Molarity and not molality, which is written with capital letter)
V= 10.5 l
n = ?
Formulas:
M = n / V => n = M * V
n = mass in grams / molar mass => mass in grams = n * molar mass
Solution
n = 1.50 * 10. 5 l = 15.75 moles
molar mass CaCO3 = 40.08 g/mol + 12.01 g/mol + 3* 16 g/mol = 100.09 g/mol
mass in grams = 15.75 moles * 100.09 g/mol = 1,576.4 g.
Answer: 1,576 g
