Respuesta :

Hippalectryon
The reaction is [tex]3Cu+2Al^{3+}\rightarrow3Cu^{2+}+2Al[/tex]

The semi equations are hence the following : [tex]Cu-=Cu^{2+}+2e^-, Al^{3+}+3e^-=Al[/tex]

The substance being reduced is the one that gets the electrons.

Hence here it's Al