abragg1128ov82ql
abragg1128ov82ql abragg1128ov82ql
  • 26-09-2017
  • Mathematics
contestada

Solve x3 = 125 over 27. 25 over 9 ą25 over 9 5 over 3 ą5 over 3

Respuesta :

fijiless
fijiless fijiless
  • 26-09-2017
 x^3 = 125/27 

Real solution: 
x = (125/27)^(1/3) = 5/3 

NOTE: -5/3 is not a solution, because 
(-5/3)^3 = (-5/3) * (-5/3) * (-5/3) = -125/27
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