Respuesta :

mathstudent55

Answer:

[tex] f'(x) = -2e^{-2x} + 3e^{3x} [/tex]

Step-by-step explanation:

[tex] f(x) = e^{-2x} + e^{3x} [/tex]

Recall:

[tex] \dfrac{d}{dx} e^x = e^x [/tex]

[tex] f'(x) = -2e^{-2x} + 3e^{3x} [/tex]

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