cooperdick79ovdub9 cooperdick79ovdub9
  • 28-08-2017
  • Mathematics
contestada

A rectangular sandbox has a width of 5 feet the sandbox is 5 times as long as it is wide

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apologiabiology
apologiabiology apologiabiology
  • 28-08-2017
you did not ask a question
I will solve for the length and the area and the perimiter

if the width is 5ft and the length is 5 times as long as it is wide then
W=5 and L=5W
subsitute 5 for W
L=5(5)
L=25

length=25ft

the perimeter=2(L+W)=2(25+5)=2(30)=60ft

the area=LW=(5ft)(25ft)=125ft²
Answer Link
liciteddy2ovdnx4
liciteddy2ovdnx4 liciteddy2ovdnx4
  • 28-08-2017
what you know:
-the width is 5ft
-length = 5 × width

to find length:
5 × w
5×5= 25

to find area:
L × W
25 × 5 = 125 ft^2

to find perimeter:
(2 × L) + (2 × W)
2 (25) +2 (5) = 60 ft
Answer Link

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