Respuesta :

tahanirish
you have only exchange every t to a
g(a)= (3a-t5)^2+4a-1
----------------------------------
and here every t by a+2
g(a+2)=(3(a+2)-5)^2+4(a+2)-1
=(3a+2-5)^2+4a+8-1
=(3a-3)^2+4a+7

Otras preguntas