Answer:
quotient=3x²+13x+36
remainder=115
Step-by-step explanation:
[tex]\begin{array}{c|cccc}&x^3&x^2&x&1\\---&--&--&--&--\\&3&4&-3&7\\x=3&&9&39&108\\---&--&--&--&--\\&3&13&36&115\\\end {array}\\\\\\3x^3+4x^2-3x+7=(x-3)(3x^2+13x+36)+115[/tex]
Thanks to rishiraj39 to delete my answer to the question
