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30-06-2017
Mathematics

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find the zeros of y=x^2-4x-9 by completing the square

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konrad509 konrad509

30-06-2017

[tex]x^2-4x-9=0\\ x^2-4x+4-13=0\\ (x-2)^2=13\\ x-2=-\sqrt{13} \vee x-2=\sqrt{13}\\ x=2-\sqrt{13} \vee x=2+\sqrt{13}[/tex]

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