Respuesta :

PHDFlopper
[tex] n^{3} [/tex]-4[tex] n^{2} [/tex]+6n-24
factor out [tex] n^{2} [/tex] from the first two values and 6 from the last two values:
[tex] n^{2} [/tex](n-4)+6(n-4)
([tex] n^{2} [/tex]+6)(n-4) is your final answer

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