georgios99
georgios99
29-04-2017
Mathematics
contestada
evaluate 7 sigma notation n=1 2(-2)^n-1
Respuesta :
irspow
irspow
29-04-2017
This is a geometric of the form:
a(n)=2(-2)^(n-1)
And the sum of any geometric sum is:
s(n)=a(1-r^n)/(1-r) in this case:
s(n)=2(1-(-2^n))/(1--2)
s(n)=2(1-(-2^n))/3 so
s(7)=2(1-(-2^7))/3
s(7)=2(1--128)/3
s(7)=2(129)/3
s(7)=86
Answer Link
josettea2004
josettea2004
04-03-2021
Answer:
the answer is D .86
Step-by-step explanation:
Answer Link
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