katelynconley20 katelynconley20
  • 27-04-2017
  • Mathematics
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find the axis of symmetry for this parabola y=-5x^2-10x-15 write it as an equation

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apologiabiology
apologiabiology apologiabiology
  • 27-04-2017
axis of symmetry is the x value of the vertex

the x value of the vertex, in form
y=ax^2+bx+c is -b/(2a)

so
y=-5x^2-10x-15
a=-5
b=-10

x value of vertex is -(-10)/(2*-5)=10/-10=-1
x=-1 is axis of symmetry
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daniellevilla8
daniellevilla8 daniellevilla8
  • 27-04-2017
x= -1
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