stan12
stan12 stan12
  • 29-03-2017
  • Mathematics
contestada

the length of a rectangle is twice the width. the area is 512yds^2 find length and width

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jdoe0001 jdoe0001
  • 29-03-2017
so.. hmm notice the picture below

since we know the length is twice "w" or 2w  then

[tex]\bf A=(2w)(w)\qquad A=512\implies 512=(2w)(w) \\\\\\ 512=2w^2\implies \cfrac{512}{2}=w^2\implies \sqrt{\cfrac{512}{2}}=w[/tex]

what's the length? well, 2w
Ver imagen jdoe0001
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