amandasan98
amandasan98 amandasan98
  • 28-03-2017
  • Mathematics
contestada

Find all solutions of the equation in the interval [0,2pi)
8sec^2x+4tan^2x-12=0

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rcukierkorn
rcukierkorn rcukierkorn
  • 29-03-2017
π/6+2πk
5π/6+2πk
you need to factor and use trig identities

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sadiq114 sadiq114
  • 30-03-2017
8(1+tan^2x)+4tan^2x-12=0.
8+12tan^2x-12=0
12tan^2x=4
tanx=1/sqrt(3)
x=atan(1/sqrt(3))
x=0.5236
Answer Link

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