Given the equation ;
[tex]2x^2+10x+1=0[/tex]The general solution of the equation is :
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]From the given equation ;
a = 2 , b = 10 , c = 1
so,
[tex]\begin{gathered} x=\frac{-10\pm\sqrt[]{10^2-4\cdot2\cdot1}}{2\cdot2}=\frac{-10\pm\sqrt[]{92}}{4} \\ So, \\ x=\frac{-10+\sqrt[]{92}}{4}=-0.102 \\ OR \\ x=\frac{-10-\sqrt[]{92}}{4}=-4.898 \end{gathered}[/tex]So, the solution is :
A = -4.898
B = -0.102
