SawyerP80293 SawyerP80293
  • 31-10-2022
  • Mathematics
contestada

what are the roots of the equation? x^2+24=14×

Respuesta :

WimberlyK675020 WimberlyK675020
  • 31-10-2022
[tex]\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}[/tex]

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