If a rectangle's width is at (5,0) and (-5,0) and the length is triple the width, what is the perimeter of the rectangle
step 1
Find the width of rectangle
subtract the x-coordinates to calculate the width
W=5-(-5)
W=10 units
step 2
Find the length
Remember that
the length is triple the width
so
L=3W
L=3*(10)
L=30 units
step 3
Find the perimeter
the perimeter of rectangle is equal to
P=2(L+W)
substitute the values
P=2(30+10)
P=2(40)
P=80 units
the answer is
perimeter of rectangle is 80 units
