Explanation:
According to the next equation,
2Li + Cl₂ → 2 LiCl (completed and balanced)
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The oxidation state of each element changes as follows:
Li) goes from 0 to +1
[tex]2Li^0=>\text{ Li}^{+1}+\text{ 2e}^{-1}[/tex]Cl) goes from 0 to -1
[tex]2Cl^0+2e^{-1}=>2Cl^{-1}[/tex](these equations above are the half-reactions)
Therefore,
Answer:
Lithium undergo oxidation
Chlorine undergo reduction
