ShahzadN252163 ShahzadN252163
  • 31-10-2022
  • Mathematics
contestada

8x10⁵ is how many times as great as 8x10 negative 1

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KeltyH229705 KeltyH229705
  • 31-10-2022

Explanation:

To find how many times is one number greater than another number we have to find the quotient between the two of them:

[tex]\frac{8\times10^5}{8\times10^{-1}}=\frac{8}{8}\times\frac{10^5}{10^{-1}}=10^{5-(-1)}=10^{5+1}=10^6[/tex]

Answer:

8x10⁵ is 10⁶ times greater than 8x10⁻¹

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