The rule for a 90 counterclockwise rotation is
[tex](x,y)\longrightarrow(-y,x)[/tex]
From the given picture, we can see that the triangle has vertices at
[tex]\begin{gathered} (-3,-2) \\ (-5,-4) \\ (-1,-5) \end{gathered}[/tex]
after applying the rule from above, we get
[tex]\begin{gathered} (-3,-2)\longrightarrow(2,-3) \\ (-5,-4)\longrightarrow(4,-5) \\ (-1,-5)\longrightarrow(5,-1) \end{gathered}[/tex]
Then, the triangle will be
