Given data
*The given mass of the soccer ball is m = 0.35 kg
*The player kicks with a force is F = 1304 N
*The time is t = 0.03 s
The formula for the change in momentum of the soccer ball during the kick is given as
[tex]\Delta p=F\times t[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \Delta p=1304\times0.03 \\ =39.12\text{ kg.m/s} \end{gathered}[/tex]Hence, the change in momentum of the soccer ball during the kick is 39.12 kg.m/s
