JioJ408596 JioJ408596
  • 31-10-2022
  • Physics
contestada

A car traveling at 4.4 m/s accelerates at the rate of +0.63 m/s2 for an interval of 5.4 s. Find vf.

Respuesta :

SalmaY267364 SalmaY267364
  • 31-10-2022

Given data

*The given speed of the car is u = 4.4 m/s

*The given acceleration of the car is

[tex]a=+0.63m/s^2[/tex]

*The given time is t = 5.4 s

The formula for the final speed of the car is given as

[tex]v_f=u+at[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} v_f=(4.4)+(0.63)(5.4) \\ =7.80\text{ m/s} \end{gathered}[/tex]

Hence, the final speed of the car is 7.80 m/s

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