ANSWER :
Graph A
EXPLANATION :
From the problem, we have the equation :
[tex]3x+4y=12[/tex]
Get the x and y-intercepts :
Let x = 0,
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
The y-intercept is (0, 3)
Let y = 0
3x + 4(0) = 12
3x = 12
x = 12/3
x = 4
The x-intercept is (4, 0)
The option that a line intersects the x-axis at (4, 0) and the y-axis at (0, 3) is graph A
