Given:
[tex]\begin{gathered} h(r)=\sqrt{4}-r............(1) \\ 3h(r)+2=4..............(2) \end{gathered}[/tex]
To find:
The value of r.
Explanation:
Using function (1) in (2),
[tex]\begin{gathered} 3(\sqrt{4}-r)+2=4 \\ 3(2-r)=4-2 \\ 6-3r=2 \\ -3r=-4 \\ r=\frac{4}{3} \end{gathered}[/tex]
Therefore, the value of r is,
[tex]\frac{4}{3}[/tex]
Final answer:
The value of r is,
[tex]\frac{4}{3}[/tex]
