Answer:
[tex]x=-15,x=-1[/tex]
Explanation:
We are given:
[tex]x^2+16x+15[/tex]
We will find the zeros of the polynomial as shown below:
[tex]\begin{gathered} x^2+16x+15=0 \\ \text{Factorise, we have:} \\ x^2+15x+x+15=0 \\ x(x+15)+1(x+15)=0 \\ x+15=0,x+1=0 \\ x=-15,x=-1 \\ \\ \therefore x=-15,x=-1 \end{gathered}[/tex]
Therefore, the correct option is: -1 and -15
