MontrellM103092 MontrellM103092
  • 30-10-2022
  • Mathematics
contestada

The function P(t) = 1001.05)×

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RomanaI583762 RomanaI583762
  • 30-10-2022

we have the function

P(t)=100(1.05^t)

For the year 2010

t=2010-1992=18 years

substitute

P(t)=100(1.05^18)

P(t)=240.66 -------> is in thousands

so

P(t)=240,660

therefore

the answer is'option B (241,000)

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