Answer: The standard form of the circle equation is:
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2\rightarrow(1) \\ \\ \\ \\ (h,k)=(x,y)\rightarrow\text{ Center of the circle} \end{gathered}[/tex]
According to the equation (1) we can have the following answer:
[tex]\begin{gathered} r=\text{ 8}\rightarrow r^2=8^2=64 \\ \\ (h,k)=(x,y)=(0,0)\text{ }\rightarrow\text{ Center} \\ \\ \therefore\rightarrow \\ \\ (x)^2+(y)^2=64\text{ }\rightarrow\text{ Option\lparen A\rparen} \end{gathered}[/tex]
