MyriahX117592 MyriahX117592
  • 30-10-2022
  • Mathematics
contestada

true or false18. In the circle: x2+(y-2)2=12, the radius is 12

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CorbinD296030 CorbinD296030
  • 30-10-2022

ANSWER

False

EXPLANATION

The equation of a circle is:

[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]

Where (x0, y0) is the center of the circle and r is the radius.

If we have the equation of a circle:

[tex]x^2+(y-2)^2=12[/tex]

x0 = 0 and y0 = 2. Therefore the center of the circle is at point (0, 2). Also, we have that:

[tex]r^2=12[/tex]

Solving for r, the radius of this circle is:

[tex]r=\sqrt[]{12}[/tex]

Therefore, it is false that the radius of the given circle is 12.

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