ZhuriJ207700 ZhuriJ207700
  • 30-10-2022
  • Mathematics
contestada

How many combinations are possible without repeats for C(6,2)

Respuesta :

GrigoriyN638413 GrigoriyN638413
  • 30-10-2022

The combinations can be calculated using the following formula:

[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]

In our case n=6 and r=2, then:

[tex]C(6,2)=\frac{6!}{2!(4)!}=\frac{2*3*4*5*6}{2*2*3*4}=\frac{5*6}{2}=15[/tex]

Hence the answer is 15

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