Knowing that AB is parallel to EC, we can say that the proportion between DC and CB is equal to the proportion between DE and EA. Then:
[tex]\frac{DC}{CB}=\frac{DE}{EA}[/tex]
Finally, we replace each value:
[tex]\begin{gathered} \frac{y}{8}=\frac{6}{x} \\ y=\frac{6\cdot8}{x} \\ \therefore y=\frac{48}{x} \end{gathered}[/tex]
Answer: Option a
