Solution:
Given the circle:
The length, L of the arc is;
[tex]\begin{gathered} L=\frac{\theta}{360}\times2\pi r \\ \\ \theta=90^o,r=16ft \end{gathered}[/tex]
Thus;
[tex]\begin{gathered} L=\frac{90}{360}\times2\pi(16) \\ \\ L=8\pi ft \end{gathered}[/tex][tex]\begin{gathered} L=\frac{90}{360}\times2\pi(16) \\ \\ L=8\pi ft \end{gathered}[/tex]
CORRECT OPTION: A
