To solve the exercise, we can use a rule of three:
[tex]\begin{gathered} 1\operatorname{km}\rightarrow1000m \\ 322\operatorname{km}\rightarrow x \end{gathered}[/tex][tex]\begin{gathered} x=\frac{322\operatorname{km}\cdot1000m}{1\operatorname{km}} \\ x=\frac{322\cdot1000m}{1} \\ x=322\cdot1000m \\ x=322,000m \end{gathered}[/tex]Therefore, the falcon can fly 322,000m/hour or 322,000 meters per hour.
