Answer:
D. -1
Explanation:
Given the quotient:
[tex]\frac{n}{4}[/tex]If the remainder of n/4 is 2, it means that the number n can be defined as follows:
[tex]\begin{gathered} n=4x+2 \\ x\text{ the number of multiples of 4} \end{gathered}[/tex]Clearly, the number n above is an even number.
When the complex number 'i' is raised to an even power, say 2, we have:
[tex]\begin{gathered} i^2=(\sqrt[]{-1})^2 \\ =-1 \end{gathered}[/tex]Therefore, the value of i^n if the remainder of n/4 is 2 is -1.
