Respuesta :

From the triangle CDF, we can see that it is an isosceles triangle.

[tex]\begin{gathered} \\ \sin \text{ 45 =}\frac{CF}{12\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{CF}{12\sqrt[]{2}} \\ CF\text{ = 12} \end{gathered}[/tex]

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