Respuesta :

Recall that:

[tex]sin\theta=cos(90^{\circ}-\theta).[/tex]

Therefore:

[tex]sin37^{\circ}=cos(90^{\circ}-37^{\circ}).[/tex]

Simplifying the above result, we get:

[tex]sin37^{\circ}=cos53^{\circ}.[/tex]

Answer:

[tex]\begin{equation*} cos53^{\circ}. \end{equation*}[/tex]

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