Solution
Solve the equation below;
[tex]81^x=27^{x+2}[/tex]Step 1: Apply exponent rules
[tex]\begin{gathered} 81^x=27^{x+2} \\ 3^{4x}=3^{3\left(x+2\right)} \end{gathered}[/tex]Step 2: solve for the value of x
[tex]\begin{gathered} 3^{4x}=3^{3\left(x+2\right)} \\ 4x=3\left(x+2\right) \\ 4x=3x+6 \\ 4x-3x=6 \\ x=6 \end{gathered}[/tex]Therefore the value of x = 6
