JohndavidC686968 JohndavidC686968
  • 30-10-2022
  • Physics
contestada

A weightlifter lifts a 105 KG barbell and a height of 1.95 m in a .25 seconds how much power is demonstrated by the left

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MacksU91886 MacksU91886
  • 30-10-2022

Answer:

8026.2 J/s

Explanation:

The power can be calculated as:

[tex]P=\frac{W}{t}=\frac{Fd}{t}[/tex]

Where W is the work done and it is equal to the force done times the distance and t is the time.

In this case, the force is equal to the weight, so the force will be

F = (105 kg)(9.8 m/s²) =1029 N

Then, replacing the force F = 1029 N, the distance d = 1.95 m and the time t = 0.25 seconds, we get

[tex]P=\frac{(1029N)(1.95m)}{0.25s}=8026.2\text{ J/s}[/tex]

Therefore, the power is 8026.2 J/s

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